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3-2x^2=3
We move all terms to the left:
3-2x^2-(3)=0
We add all the numbers together, and all the variables
-2x^2=0
a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-4}=0$
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